www.3.chem21labsc : Chem21 Reference Mater x Length -) C www3.chem21labs.com/stu

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www.3.chem21labsc : Chem21 Reference Mater x Length -) C www3.chem21labs.com/student2/index cfr ?mode-assign&assignment-276;&postlab; 1 mol CC4 150 Ca4 1000 mg CC4 5.326E19 cules CCl4 6.022E23 cule CC4 1 mol CC4 1 g CC4 A liquid contains 5.326E19 molecules of carbon tetrachloride [CCI4], what mass (in mo) of CCla is present? Densitycc4 = 1.594 g/mL Click the Eef The Molar Mass Must Be Reported To At Least 2 Decimal Places On This Website! Click on the ChemconneXions Map below and Mouse over the Instructions Button for more details. Pay Attention To The Number Of Significant Figures Required In The Answerl Enter the actual number or express it in Scientific Notation in the format 1.23E-4 (no spaces) If your answer is incorrect, scroll down the page and look at the hints under your answer to take st aterial link at the top of this page and then the link. Click on the Periodic Table a ll down the page and look at the hints under your answer to take steps Dimensional Analysis Ma 1. pl. Yard U Fe Quar

Explanation / Answer

Solution :-

Molecules are given so convert them to moles and the moles to mass in gram and then gram to mg

5.326*10^19 moleucles of CCl4 * 1 mol / 6.022*10^23 molecules )*(153.82 g/1 mol CCl4)*(1000 mg / 1 g) = 13.60 mg CCl4

So the answer is 13.60 mg CCl4

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