Answer the following questions using the chemical reaction and thermochemical in

Question

Answer the following questions using the chemical reaction and thermochemical information given below:



CH3OH(g) 2H2(g) + CO(g)

1. Determine G°rx (in kJ) for this reaction at 1173.15 K. Assume H°f and S° do not vary as a function of temperature. Report your answer to two decimal places

2-Determine the equilibrium constant for this reaction. Report your answer to three significant figures in scientific notation.

Hf° (kJ/mol)     S° (J mol-1 K-1) CH3OH -201.50 239.80 H2 0.00 130.68 CO -110.53 197.66

Explanation / Answer

Answer – 1) In this one there is given, reaction - CH3OH(g) <--->2H2(g) + CO(g)

We need to calculate the Gorxn at 1173.15 K

First we need to calculate the Horxn and Sorxn

We know Ho rxn is ,

Ho rxn = sum of the Ho product – sum of the Ho reactant

               = [2*Ho H2 + HoCO ] – [Ho CH3OH (g)]

             = ( 2*0.00 + -110.53 ) - (-201.5)

                = 90.97 kJ/mol

We know So rxn is ,

So rxn = sum of the So product – sum of the So reactant

               = [2*So H2 + SoCO ] – [So CH3OH (g)]

             = ( 2*130.68 + 197.66 ) - (239.80)

                = 219.22 J/mol.K

We know the formula,

Gorxn = Ho -T So

        = 90970 J – 1173.15 K * 219.22 J/K

      = -166208 J

       = -166.21 kJ

2) Now we know the formula

Go = -RT ln Kp

Now plugging the values in the formula,

-166208 J = -8.314 *1173.15 * ln Kp

ln Kp = 166208 J / 8.314 *1173.15

          = 17.04

Taking antiln from both side

Kp = 2.52*107

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