saplinglearning.com JagMall Sakal Paws CH132 Sapling Church YouTube emistry 11-S

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saplinglearning.com JagMall Sakal Paws CH132 Sapling Church YouTube emistry 11-Stenson Activities and Due Dates Homework 3 2/10/2016 11:55 PM 4 66.3/1002/10/2016 12:13 PM 3 Gradebo Print Calcitr Periodic Table Question 19 of 19 Map The decomposition of N-Os can be described by the equation t (s) | pol (M) 1.87 155 170 526 1.34 766 11.16 Given these data for the reaction at 45 in carbon tetrachionde solution, calculate the average rate of reaction for each successive time interval Interval:0 s to 155s 155 s to 526s 526 s to 765s Number Numbor Number Reaction rate: M/s M/s M/s Previous Give up & View Solution

Explanation / Answer

Rate of reaction   = Change in concentration/ time intravel

         0 to 155 sec

                             = 1.87--1.7/155-0

                            = 0.001096 M/sec

Rate at 155 to 526sec

rate                    = 1.7--1.34/526--155

                          = 9.7*10-7 M/sec

Rate at 526 to 765 sec

Rate                    = 1.34--1.16/765--526

                         = 7.53*10-4 M/sec

   

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