What is the theoretical yield for Co II (salen)? H 2 (salen) + [Co II (OAc) 2 ]
ID: 988634 • Letter: W
Question
What is the theoretical yield for CoII(salen)? H2(salen) + [CoII(OAc)2] * 4H2O ------> CoII(salen) * 2H2O
Experiment Guide:
Synthesis of CoII(salen) complex • In a 250 mL Erlenmeyer flask, stir 10 mmol H2salen (2.68 g) in 40 mL of ethanol under reflux (boiling). • Add 10 mmol cobalt(II) acetate tetrahydrate [CoII(OAc)2•4H2O, 2.49 g] slowly. • After stirring for 30 min, let the solution cool to near room temperature. Pay attention to the color change during this step. • Recover the solid product by suction filtration through filter paper in a Büchner funnel on a filter flask. Rinse with diethyl ether. • Determine the yield of the dry solid
Explanation / Answer
10 mmol H2salen (2.68 g) and 10 mmol cobalt(II) acetate tetrahydrate will give 10 mmol of CoII(salen) * 2H2O
Molecular formula of CoII(salen) = C16H18CoN2O4
Molar mass of C16H18CoN2O4 is 361.2583 g/mol
weight of 10 mmol of CoII(salen) = 10 x 361.2583 = 3.612583 gm
theoretical yield for CoII(salen) is = 3.612583 gm
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.