One of the dye molecules used in the beads is shown below. In this condensed che

Question

One of the dye molecules used in the beads is shown below. In this condensed chemical structure, the C and H atoms are not shown explicitly. Carbon atoms are located at the vertex of two lines. The hydrogen atoms fill in to satisfy the octet rule (carbon never has lone pairs in normal molecules). See Chapter 10 for some examples. If you assume that R = H, and X = F, what is the chemical formula for the leuco form of the dye? Now, here's the real question, what happens to the shape of the molecule when it goes from the colorless leuco form to the colored form? Specifically, what happens to the geometry about the C-atom that is circled?

Explanation / Answer

a) The chemical formula remains the same since no atom is lost or gained and it is : C20 H16 N2 F O

b) when the molecule goes from colorless form to colored form, the molecule goes from tetrahedral form to a planar form with only two carbon and one oxygen not in the plane

c) the geometry of the circled atom changes from tetrahedral to planar, since the hybridization changes from sp3 to sp2

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