A 25.0 g metallic coin was placed in a sub-zero freezer until it reached a tempe

Question

A 25.0 g metallic coin was placed in a sub-zero freezer until it reached a temperature of -15.00degreeC. This coin was placed in a calorimeter containing 50.0 g of water, initially at a temperature of 36.00degreeC. The final temperature of the coin and water was 12.00degreeC. What is the specific heat of the metal? You may assume that no heat was lost to the calorimeter. This same metallic coin was heated to a temperature of 45.00degreeC and placed in a calorimeter containing 50.0 g of water, initially at a temperature of 18.00degreeC. What is the final temperature of the coin and the water? You may assume that no heat was lost to the calorimeter.

Explanation / Answer

3b) Since we have calculated the specific heat of the coin to be 1.78 cal/goC.

1.8 x 25 x deltaT = 1 x 50 x delta T

45 x delta T = 50 x delta T

45 x (45 - X) = 50 x (X - 18)

2025 - 45X = 50X - 900

2025 + 900 = 50X + 45X

2925 = 95X

X = 30.79 oC

This is the final temperature of the coin and water.

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