What is the entropy change for the freezing of one mole of water at 0 degreeC? T

Question

What is the entropy change for the freezing of one mole of water at 0 degreeC? The heat of fusion is 333.5 J g^1. (at wts:H=1.00, 0=18) A liter vessel containing 0.233 mol of N_2 and 0.341 mol of PC1_5 is heated to 250 degreeC. The total pressure at equilibrium is 29.33 bar, Assuming that all the gases are ideal, Calculate K for the only reaction that occurs Two blocks of the same metal having equal masses but at different temperatures T_1 and T_2, are brought in thermal contact and allowed to come to the same temperature, T_f. The entropy change is

Explanation / Answer

5A. Entropy change for the freezing of 1 mole of water

1 mol of water = 18 g water

S = mH/T = -18g ( 333.5 J/mol)/273 K

5B. Maxwell Relationship

TdS - PdV

All your remaining answers are correct

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