Complete and balance the following: H_2SO_3 + Ba(OH)_2 Consider the following ba

Question

Complete and balance the following: H_2SO_3 + Ba(OH)_2 Consider the following balanced acid/base reaction: 2H_3PO_4 + 6KOH 3H_2O + 2K_3PO_4 A student pipetted 25.00 mL of a KOH solution into an Erlenmeyer flask. The student calculated that 16.25 mL of 0.116 M H_3PO_4 was needed to neutralize the base. Calculate the number of moles of H_3PO_4 delivered to the flask. Calculate the molarity of KOH solution. For the following questions make sure that you follow the sig fig rules for log values (see document on the common BB site) What is the [H_3O^+] in an aqueous solution that has [OH] =2.8 times 10^-9.M. Calculate the pH for a solution that has [OH^-] = 1.65 times 10^-11 M A solution has a pH of 2.68. What is the [H_3 O^+] in this solution?

Explanation / Answer

Question 5

Here we have a neutralization reaction between an acid and a base thus we're going to produce water and a salt:

H2SO3 + Ba(OH)2 -> H2O + BaSO3

Let's remember that when we balance chemical equations we start with metals, then non-metals and at the end H and O, so let's start with Ba: we have 1 atom of Ba in each side of the equation.

Let's move to balance the S, we have 1 atom of S in each side of the equation too.

Let's move to balance O, we have 5 atoms of O in the left side and 4 on the right side. We place a 2 before H2O so S and Ba stay unaltered:

H2SO3 + Ba(OH)2 -> 2H2O + BaSO3

Now we have 5 O in each side.

Finally let's move to balance H, we have 4 in the left side and also 4 on the right side.

So the balanced equation is:

H2SO3 + Ba(OH)2 -> 2H2O + BaSO3

Question 7

Let's remember the ionic product of water:

kw = (H3O+)(OH-).

kw has a value of 1 x 10-14 M2 at room temperature.

We have kw and (H3O+) so let's solve for (OH-):

(OH-) = kw/(H3O+)

(OH-) = 1 x 10-14 M2/ 2.8 x 10-9 M

(OH-) = 3.6 x 10-6 M

Note: we are only allowed to answer to 1 question per Q&A but I extra helped you with Question 7. Please ask for question 6 in another Q&A and you can ask both 8 and 9 on another one.

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