What is the pH of a 0.053 M solution of KOH at 25 degreeC? (A) 13.11 (B) 12.72 (
ID: 994106 • Letter: W
Question
What is the pH of a 0.053 M solution of KOH at 25 degreeC? (A) 13.11 (B) 12.72 (C) 1.28 (D) 0.89 14. What volume (in mL) of 0.100 M barium hydroxide, Ba(OH)_2, is needed to completely neutralize 25.0 mL of 0.100 M hydrochloric acid, HCI? (A) 75.0 mL (B) 50.0 mL (C) 25.0 mL (D) 12.5 mL 15. Which species is the oxidizing agent in the reaction: Cr^3+(aq) + Fe(s) rightarrow Cr(s) + Fe^3+(aq)? (A) Cr(s) (B) Fe(s) (C) Cr^3+(aq) (D) Fe^3+(aq) 16. Propane, C_3H_8, is used in a propane-oxygen fuel cell, for which the overall reaction is the combustion of propane. The anode half-cell reaction is: C_3H_8(g) + 6 H_2O(I) rightarrow 3 CO_2(g) + 20 H*(aq) + 20 e^- What is the cathode half-cell reaction? (A) O_2(g) + 4H^+(aq) + 4e^- rightarrow 2H_2O(l) (B) O_2(g) + 2H^+(aq) + 2e^- rightarrow H_2O_2(aq) (C) 2H^+(aq) + 2e^- rightarrow H_2(g) (D) 2H_2O(I) + 2e^- rightarrow H_2(g) + 2OH^-(aq) 17. When balancing this half-reaction in basic solution, electrons are added to the side of the equation. MnO_4^- (aq) rightarrow MnO_2(aq) (A) 3. reactant (B) 3. product (C) 5. reactant (D) 5. product 18. What is the equilibrium constant for this reaction at 298 K? Fe^2+(aq) + VO_2^+(aq) + 2H^+(aq) rightarrow Fe^3+(aq) + VO^2+(aq) + H_2O(I) Edegree = +0.23 V (A) 8.7 times 10^29 (B) 7.8 times 10^3 (C) 9.1 times 10^2 (D) 1.3 times 10^-4 19. What is the standard cell potential for the reaction, 3Ag(s) + Au^3+ (aq) rightarrow 3Ag^+(aq) + Au(s)? (A) 3.82 V (B) 2.22 V (C) 0.62 V (D) -0.98 VExplanation / Answer
13.
pOH = -log(OH-) =-log(0.053) = 1.2757
pH = 14-1.2757 = 12.725
14.
mmol of acid = MV = 25*0.1 = 2.5 mmol of acid
mmol of base has 1:2 ratio so
2.5/2 = 1.25 mmol of base
V = mmol/M = 1.25/0.1 = 12.5 mL
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