QUESTION 17 If the pKa of HCHO 2 is 3.74 and the pH of an HCHO 2 /NaCHO 2 soluti
ID: 994278 • Letter: Q
Question
QUESTION 17
If the pKa of HCHO2 is 3.74 and the pH of an HCHO2/NaCHO2 solution is 3.74, which of the following is TRUE?
[HCHO2] > [NaCHO2]
[HCHO2] < <[NaCHO2]
[HCHO2] < [NaCHO2]
[HCHO2] = [NaCHO2]
It is not possible to make a buffer of this pH from HCHO2 and NaCHO2.
4 points
QUESTION 18
The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.
H2(g) + Br2(g) 2 HBr(g) Kc = 3.8 × 104
2 HBr(g) H2(g) + Br2(g) Kc = ?
QUESTION 19
The molar solubility of ZnS is 1.6 × 10-12 M in pure water. Calculate the Ksp for ZnS.
Explanation / Answer
17) [HCHO2] = [NaCHO2]
pKa = 3.74
pH = 3.74
pH = pKa + log [salt /acid]
3.74 = 3.74 + log [NaCHO2/HCHO2]
[NaCHO2/HCHO2] = 1
NaCHO2 = HCHO2
18) Kc = 2.6 x 10^-5
H2(g) + Br2(g) 2 HBr(g) Kc = 3.8 × 10^4
2 HBr(g) H2(g) + Br2(g)
Kc = 1 / 3.8 × 10^4
Kc = 2.6 x 10^-5
19)
ZnS -------------------> Zn+2 + S-2
S S
Ksp = [Zn+2][S2-]
1.6 × 10^-12 = S^2
S = 1.26 x 10^-6 M
molar solubility = 1.26 x 10^-6 M
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