Question 10 of 15 Mapoob sapling learning Low concentrations of warfarin near th

Question

Question 10 of 15 Mapoob sapling learning Low concentrations of warfarin near the detection limit gave the following dimensionless instrument readings: 171.9, 135.3, 128.9, 140.9, 185.9, 126.7, 189.7, 168.3, 101.3, and 172.1. Ten blanks had a mean reading of 49.7. The slope of the calibration curve is 1.96x 109 M-1 Estimate the signal and concentration detection limits and the lower limit of quantitation for warfarin. Number Signal Detection Limit: Number Concentration Detection Limit: Number Lower Limit of Quantitation: Previous Give Up & View Solution e Check Answer 0 Next Exit- Hint

Explanation / Answer

Standard deviation = 29.40

mean given = 49.7

signal = mean + 3x SD

=49.7+3x29.40

=137.90

CDL = 3.3 X SD / s

=3.3x29.40 / 1.96*109

=5*10-8

Lower limit of quantitation ==10 X SD / s

=10x29.40 / 1.96*109

=15*10-8

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