In another cell, the potential of the copper metal, copper(II) ion electrode was

Question

In another cell, the potential of the copper metal, copper(II) ion electrode was found to be 0.442 V relative to a silver metal, silver ion electrode, with the copper electrode being negative. If the potential of the silver, silver ion electrode, E^0_Ag, Ag is taken to be 0.000 V in oxidation or reduction, what is the value of the potential for the oxidation reaction. E^0_cu cu^2+ oxid E^0_cell = E^0_oxide + E^0_red. + volts If E^0_Ag^+ Ag red equals +0.799V. as in standard tables of electrode potentials, what is the value of the potential of the oxidation reaction of copper, E^0_cu, cu^2+ oxid volts The student adds 6 M NH_3 to the CuSO_4 solution in this second cell until the Cu^2+ ion is essentially all converted to Cu(NH_3)_4^2+ ion. The voltage of the cell. E_cell, goes up to 0.917 V and the Cu electrode is still negative. Find the residual concentration of Cu^2+ ion in the cell. (Use Eq. 4.)

Explanation / Answer

a. If the potential for the Ag+, Ag electrode is 0:

E0 Cu, Cu+2 = 0 + 0.442 V = 0.442 V

b. Now E0 for Ag+, Ag has a value:

0.442 V = E0 Cu, Cu+2 - 0.799 V

E0 Cu, Cu2+ = 0.442 + 0.799 = 1.241 V

c. Eq. 4 info is missing.

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