Assume i atm pressure. Can you explain the trend ment between calculation and ex

Question

Assume i atm pressure. Can you explain the trend ment between calculation and experiment? Calculate S for 1 mol of Hg vapor at 298. 15 K if its pressure at that temperature is 0. 001960 torr. 17. 52. Given a mol of^12C(g) and^13C(g), determine the ratio of the partition functions at the same volume and temperature. Without calculating an actual number, can you determine which one will have a larger value of q? 17. 53. According to the Sackur-Tetrode equation, is S proportional or inversely proportional to these state variables? (a) temperature (b) pressure. Do your answers agree with phenomenological thermodynamics' predictions on the variation of S with these variables? 17. Use equation 17. 56 to determine the change in energy, DeltaF, when 1 mole of Ar is heated from 298 K to 348 K at constant volume. Compare this result with the change in energy calculated using (mass)(specific heat)(change in temperature). The specific heat of argon is 20. 79 J/(mol-K).

Explanation / Answer

your normal press to T 298 is 760torr for 1 liter as it is to 1.96x10-3torr = 2.57x10-6 atm have a change of V for a ideal gas have

PV = nRT =) V = nRT/P V = 0.082atml/molk x 298Kx 1mol/2.57x10-6atm = 1.9x107l so

nRLnVf/Vo where Vo = 1l R = 8.31J/mol K x 1mol Ln (1.9x107l /1l) = 139.28 j/K

to this T 298.15 a mol of Hg your presure of vapor is 1.96x 10-3torr  and it is exposes to pressure of 760torr

in this case S = nCvLnTf/To  + nRLnVf/Vo as V have no change and T too the S = 0

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