The bonding in iron (III) nitrite is Ionic only Covalent only Metallic and coval

Question

The bonding in iron (III) nitrite is Ionic only Covalent only Metallic and covalent Ionic and metallic Ionic and covalent For questions 13-15, consider the chemical reaction that occurs when 50 g of dinitrogen tetroxide (N_2O_4, 92.02 g/mol) reacts with 47.5 g of hydrazine (N_2H_4, 32.06 g/mol) to produce nitrogen gas and water. N_2O_4(l) + 2N_2H_4(l) rightarrow 3N_2 (g) + 4H_2 O(l) If the reaction produces 30 g of nitrogen gas, what is the percent yield of this reaction? 16.9% 65.7% 31.3% 48.2% How many moles of excess reagent are left over after the reaction has run to completion if the percent yield of the reaction was 100%? 0.94 1.09 0.39 1.48 If the reaction is run at STI* and the yield is 54%, what is the maximum volume of N_2 formed (in liters)? 36.5 liters 19.7 liters 21.5 liters 39.8 liters The density of gold is 19.3 grams/cm^3. Which equation below represents the of this density to units of nanograms/m^3? Density (ng/m^3) = 19.3 Times 10^-9 Times 10^6 Density (ng/m^3) = 19.3 Times 10^-9 Times 10^2 Density (ng/m^3) = 19.3 Times 10^9 Times 10^2 Density (ng/m^3) = 19.3 Times 10^-9 Times 10^6 Consider the molecular orbital diagram of O_2 with a bond order of 2. How many must be added to the O_2 molecule to reduce the bond order to zero. 4 electrons 3 electrons 2 electrons 1 electron

Explanation / Answer

12. (e) ionic and covalent

13. (b)

2N2H4 + N2O4 3N2 + 4H2O

N2O4 moles = 50/ 92.02 = 0.5434

N2H4 moles = 47.5/ 32.06 = 1.482; required moles of N2H4 =  0.5434 X2 = 1.0868

N2O4 is the limiting substrate

so, produced N2 gas moles = 3 X 0.5434 = 1.63 moles

produced N2 gas mass theoritically (100%) = 1.63 X28 = 45.65 g

Actually produced N2 gas mass = 30 g

percentage of yield = 100/ 45.65 X 30 = 65.71%

14. (c)

the remaining N2H4 moles = 1.482 - 1.0868 = 0.395 moles

15. (b) 19.7 L

100% yield in above reaction = 1.63 moles of N2 gas production

moles of N2 gas produced if yield of reaction is 54% = 0.8802 moles

At STP, the produced N2 gas volume = 0.88 X 22.4 L = 19.712 L

16. (d)

17. (a) 4 electrons need to add to make its bond order zero.

Best wishes.

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