concentration of Na so, 002 :volume of NgSiO, (D. 201 L . Ambient temperature 21

Question

concentration of Na so, 002 :volume of NgSiO, (D. 201 L . Ambient temperature 210 Molir coneceatratio of 0.3MMolar concentration ot,o 0M Teral volume of kie s20mL Molar concentration of Na,S,O, Kinetic Trial I. Time for color 11.93s. 40.23 s 4310s-. 30.15£ 7541s 7441 s anyos change, At (sec) B. Calculations for Determining the Rate Law 1. Moles of S,O, consumed (mol) -S mol (mol/s) 3.1x (mol 1,-) 4.log A . T (mo/L) t Valums H.0, md 3.0mL 30aL 30mL 3.0m 52.0mL 30mL 3.0mL 3.0mL 3.0mL S.0 m onl 2.0mL 8. Volume H,0, (m 10.log (H,Ol Diluted initial molar concentration. -L10-1.10 -1.10 1.0 1 1201.2 140 2.00 -1.10-1.10-1:52 1-40-2.00 10. log [Hrolo Calculations for Kinetic Trial 2.0,1 0.02 L

Explanation / Answer

0.02

To calculate average k` add all divide by 7 i.e,

Avg k` = 7.029*10^-5

Standard deviation = [{(k1-k`)²+(k2-k`)²+..…..}/n-1]

= 18.42*10^-5

Relative standard deviation= 100*s/k` = 262.1098

Rate.    [I^-]. [H2O2]. [I-]^0.8.    [H2O2]^0.9 K*10^-5 5.4*10^-8 0.02 0.02 0.0437 0.029 4.261 1.7*10^-7 0.03 0.02 0.06049 0.029 9.690 2.3*10^-7 0.05 0.02 0.0910 0.029 8.7154 2.6*10^-7 0.06 0.02 0.10532 0.029 8.5126 1.3*10^-7 0.02 0.03 0.0437 0.04259 6.984 1.3*10^-7

0.02

0.04 0.0437 0.0551 5.398 3.7*10^-8 0.02 0.01 0.0437 0.015 5.6445

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