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You are to filter each solution prepared in part I.C. So that a 20 to 40 mL samp

ID: 1014557 • Letter: Y

Question

You are to filter each solution prepared in part I.C. So that a 20 to 40 mL sample of uncontaminated and undiluted supernatant is obtained. Label four clean and dry beakers. Prepare a filter paper cone for each of four clean and dry filter funnels. Pass each solution through a different dry paper cone, catching the supernatant in the appropriately labeled beaker. The solid Ca(IO3)2 and filter papers can be discarded .

B. Label four distilled water rinsed Erlynmeyer flasks and pipet 10.00 mL of each supernatant into a different flask. Add 10-20 mL of distilled water, 1cm^3 of solid KI and two droppersful of 1M HCl to each flask. Record observations.

****Our observations showed that each solution in the flasks turned a medium orange color with a red hint.

C. What conclusions can be drawn from these observations? (HINT: what ions must be present for the colored I2 to form? Where did each of these come from in these experiments? Considering the data collected to this point, what can be said about the extent to which Ca(IO3)2 dissolves?

D. Titrate each of these solutions as was done in part 2. Record titration data. Using molar concentration of stock thiosulfate solution solution determined in part 2 and the analysis reaction given there, determine the molar concentration of IO3- developed in each supernatant solution.

******Titration data:

Solution #: 1, 2, 3, 4

Initial [Ca2+] M: 0, 0.006, 0.025, 0.1

Initial buret reading mL: 24.62 , 0.31, 18.69 , 33.41, 31.59

Final buret reading mL: 46.15, 18.69, 33.41, 31.59

Total S2O3 2- volume mL : 21.53 , 18.38 , 14.72 , 12.88

Molar its IO3- (M): ?????

SIDENOTE: I only need the question in part C and D answered because I don't really understand it please include a detailed answer that explains each question. Also please include calculations for part D for each solution. I included everything else just to give you an idea of what was going on in the experiment we had conducted, Thank you in advance.

Explanation / Answer

C) here you didn't mension what did you do in part 1.but however there should be a reductive form.because here iodin ion has become I2.

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