Which member of the following pairs has the stronger intermolecular dispersion f

Question

Which member of the following pairs has the stronger intermolecular dispersion forces, and explain why?

Br2 or O2

CH3CH2SH or CH3CH2CH2SH

CH2CH2CH2CL or (CH3)CHCl

Which member of the following pairs has the stronger intermolecular dispersion forces, explain why.

CH3CH2CH2CH3 or CH3CH3

CCl4 or Cl4

P4 or Br2

What type of intermolecular forces exist between the following pairs.

< >

< >

< >

< >

What type(s) of intermolecular force is (are) common to the following pairs?

Xe and methanol(CH3OH)

< >

< >

Which of the following can form hydrogen bonds with water?

< >

< >

< >

< >

< >

Which of the following are capable of hydrogen bonding among themselves?

< >

< >

< >

(a) How do the viscosity and surface tension of liquids change as intermolecular forces become stronger? (b) How do viscosity and surface tension of liquids change as temperature increases?(c)Predict which of the following liquids has greater surface tension: ethanol (CH3CH2OH) or dimethyl ether (CH3OCH3).

(a) Distinguish between adhesive forces and cohesive forces. (b) Do viscosity and surface tension reflect adhesive forces or cohesive forces of attraction? (c) Explain the cause of the U-shaped meniscus in a glass tube. (d) Explain why as temperature increases, oil will flow faster through a narrow tube.

The Vapor Pressure of ethanol is 100 mmHg at 34.9°C.What is its vapor pressure at 63.5°C? (Hvap for ethanol is 39.3 kJ/mol.)

The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C.What is the vapor pressure at 60.6°C?(The molar heat of vaporization, Hvap, for benzene is 31.0 kJ/mol.)

Explain in terms of intermolecular forces why a

< >

< >

List the following molecules in order of increasing boiling points.Explain why.

CH3F, CH3OH, CH3NH2, and CH3Br

Calculate the enthalpy change upon converting 1.00 mol of ice at -25°C to water vapor (steam) at 125°C under constant pressure of 1 atm.The specific heats of ice, water, and steam are 2.09J/g-K, 4.18J/g-K, and 1.84J/g-K, respectively.For H2O, Hfus = 6.01 kJ/mol, and Hvap = 40.67 kJ/mol.

Solution:

What is the enthalpy change during the process in which 100.0 g of water at 50.0°C is cooled to ice at-30.0°C? (Use the specific heats and enthalpies for the phase changes given in the My Turn example.)

How many Na+ and Cl- are in each NaCl unit cell? (face-centered cubic cell)

Vanadium crystillizes in a body-centered cubic lattice (the V atoms occupy only the lattice points.)How many V atoms are present in a unit cell?

The edge length of the NaCl unit cell is 564 pm.What is the density of NaCl in g/cm3?

Metallic iron crystallizes in a cubic lattice.The unit edge length is 287 pm.The density of iron is 7.87g/cm3.How many iron atoms are within a unit cell?

Explanation / Answer

Which member of the following pairs has the stronger intermolecular dispersion forces, and explain why?

Br2 or O2 = Br2 and O2 are both nonpolar, therefore, their intermoelcular forces are mainly due to thei MASS interaction, note that Br2 mass is higher than O2, therefore, Br2 will have stronger forces

CH3CH2SH or CH3CH2CH2SH = Similar as before, the second (CH3CH2CH2SH) specie has an extra CH, therefore, higher mass, that is, stronger forces

CH2CH2CH2CL or (CH3)CHCl = Similar as before, the second (CH2CH2CH2CL) specie has an extra CH, therefore, higher mass, that is, stronger forces

Which member of the following pairs has the stronger intermolecular dispersion forces, explain why.

CH3CH2CH2CH3 or CH3CH3 = CH3CH2CH2CH3 has a higher mass than CH3CH3, therefore, stronger forces

CCl4 or Cl4 = Cl4 is not likely to exist. CCl4 is nonpolar, therefore choose CCl4 due to higher mass

P4 or Br2 = Br2 has a higher mass, therefore higher boiling point/stronger forces

For all further questions, please consider posting multiple questions in multiple set of Q&A. We are not allowed to answer to multiple questions in a single set of Q&A

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.