Given the unit-cell edge length and atomic mass, be able to calculate the densit
ID: 1016384 • Letter: G
Question
Given the unit-cell edge length and atomic mass, be able to calculate the density of a metal A metal has a face-centered lattice with all atoms at lattice points and a unit cell length of 300.0 pm Its atomic mass is 253.5 amu What is the density of the metal? (avocado's # is 6 022 x 10^23) the number of atoms in a unit cell of a lace-centered cubic. simple cubic and body centered In a first-order reaction the half-life is 350 seconds What is the rate constant, k in s^-t. Substance A undergoes a first order reaction A rightarrow B with a halt- life of 20 mm at 25 degree C If the initial concentration of A [A].) in a sample is 2.7 M what will be the concentration of A after 60 min? Write ail the possible rate expressions for a reaction e g C s_2(g) 4 H_2 (g) rightarrow CH_4(g) + 2H_2S(g) A reaction was found to be second order in carbon monoxide concentration. The fate of the reaction if the concentration of the reactant A is tripled with everything else kept the same Know the relationship between concentration and time for the integrated rate law tor first order. second order and third order reactions that give a straight line equation E g a plot of 1/|A| vs time will produce a straight line for a 2^al order reaction with a positive slope Given Delta H and Activation energy for a forward reactions. be able to calculate the activation energy for the reverse reaction Eg for the following reaction producing 1 moll of oxygen gas at a particular temperature Delta H = -200 kJExplanation / Answer
Problem 5: The half life of reaction = 20 minutes
The problem can be solved as
(i) we will calcualte the rate constant as
K = 0.693 / half life = 0.693 / 20 = 0.03465 min^-1
(ii) t = 2.303 / K (log[A0/ At] )
60 = 2.303 / 0.03465 log [2.7 / At]
0.903 = log [2.7 / At]
Taking antilog
7.99 = [2.7 / At]
At = 2.7 / 7.99 = 0.338
6) The possible rate expression will be
Rate = k [CS2] [ H2]^4
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