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Given the unbalanced equation, for the species that is the reduction product, en

ID: 815539 • Letter: G

Question

Given the unbalanced equation, for the species that is the reduction product, enter the symbol and the final oxidation state of the specific element that has a lower oxidation state. Use arabic numerals for oxidation state magnitude.

Example:

Element: Sb

Oxidation state: 0

Zn(s) + Au3+(aq) + Cl-(aq) ? Au(s) + Zn2+(aq) + Cl-(aq)

Given the unbalanced equation, for the species that is the reduction product, enter the symbol and the final oxidation state of the specific element that has a lower oxidation state. Use arabic numerals for oxidation state magnitude. Example: Element: Sb Oxidation state: 0 Zn(s) + Au3+(aq) + Cl-(aq) ? Au(s) + Zn2+(aq) + Cl-(aq) Element: Oxidation state:

Explanation / Answer

Zn(s) + Au3+(aq) + Cl-(aq) ? Au(s) + Zn2+(aq) + Cl-(aq)

1)Zn ------Zn2+

Zn changes from 0 to +2 oxidation state

here Zn is oxidised

2) Au3+(aq) -----> Au(s)

Al changes from +3 to 0 oxidation state

here Al is reduced.

3) Cl-(aq) -----> Cl-(aq)

Cl changes from -1 to -1 oxidation state

=> there is no change

=> it will neither oxidised nor reduced

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