A 2.00 mL sample of cola is diluted to 100.0 mL and then the phosphate concentra

Question

A 2.00 mL sample of cola is diluted to 100.0 mL and then the phosphate concentration of the diluted sample is found to be 8.7 x 10^-5M, what is the concentration of phosphate in the cola? Can you show and explain the steps, thank you :) A 2.00 mL sample of cola is diluted to 100.0 mL and then the phosphate concentration of the diluted sample is found to be 8.7 x 10^-5M, what is the concentration of phosphate in the cola? Can you show and explain the steps, thank you :) Can you show and explain the steps, thank you :)

Explanation / Answer

[phosphate] in diluted sample= 8.7 x 10^ -5 M

[phosphate] in cola = [C]

According to the calculation,

([C] / 1000 cm3) x (2 cm3 / 100 cm3) x 1000 cm3 = 8.7 x 10^ -5 M

Therefore,

[C] = 4.35 x 10^ -3 M

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