Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

How many centiliters are in 0.79 liters? [1 cL = 0.01L] Your Answer:Question 1 o

ID: 1024162 • Letter: H

Question

How many centiliters are in 0.79 liters? [1 cL = 0.01L]

Your Answer:Question 1 options:

Save

Question 2 (3 points)

How many milliliters are in 5.2 gallons?
[1 gallon = 3.8 L and 1 L = 1000 mL]

Your Answer:Question 2 options:

Save

Question 3 (3 points)

[The ^ symbol means raise the next number to an exponent]

3.0 x 10^-13 x 4.0 x 10^5 = 1.2 x 10^(?)

Your Answer:Question 3 options:

Save

Question 4 (3 points)

The density of copper is 10.0 g/mL. What is the volume in milliliters of a 503-g ingot of copper?

Your Answer:Question 4 options:

Save

Question 5 (3 points)

A Pascal (Pa) is defined as the pressure exerted by a force of 1 Newton (N) acting on an area of one square meter (1Pa = 1N/m^2). A Newton is represented by the follwoing units: 1N = kg x m / s^2. Which of the following are also acceptable units for a Pascal?

Question 5 options:

1Pa = 1kg^2/m^2s

1Pa = 1kg/m^2s^2

1Pa = 1kg/ms

1Pa = 1kg/ms^2

Save

Question 6 (3 points)

Solve the following equation for z:

15 = 10z/[2-(2x4)]

Your Answer:Question 6 options:

Save

Question 7 (3 points)

Express the following statement as an algebraic equation: "There are six students for every professsor at this university."

Question 7 options:

S x P = 6

6S = P

S + P = 6

6P = S

Save

Question 8 (3 points)

What is the log of 1 x 10^7?

Your Answer:Question 8 options:

Save

Question 9 (3 points)

According to the ideal gas law, PV = nRT, where:
P = pressure
V = volume
n = moles
R = constant
T = Temperature

If the volume and number of moles of gas are held constant, as the temperature increases the pressure will _____________.

Question 9 options:

Cannot be determined

Decreases

Increase

Remain the same

Answer

Explanation / Answer

1)

We have 1 cL = 0.01 L

0.79 L = 0.79L *(1 cL/0.01L)

           = 79 cL

Therefore, 0.79 L contains 79 cL

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote