REACTION STOICHIOMETRY: MASS RELATIONSHIPS IN BALANCED CHEMICAL EQUATIONSs ADVAN
ID: 1030900 • Letter: R
Question
REACTION STOICHIOMETRY: MASS RELATIONSHIPS IN BALANCED CHEMICAL EQUATIONSs ADVANCED PROBLEM ASSIGNMENT Name Section Date Complete the calculation smmary below. READ HE EXPERIMENTAL DISCUSSION FIRST! REPORT ALL ANSWERS TO THE CORRECT SIGNIFICANT FIGURES. SHOW CALCULATION SET-UP on the next page PART B Molarity Determination via Solution Stoichiometry 7.625 g Mass of Empry 50 mL. Beaker Mass of Beaker and NaCI (final heating) 7.976 g Mass of NaCI Produced (Experimental Yield of NaCI) Moles of Na,CO, Consumed Volume of Na,CO, Solution Molarity of Na,CO, Solution PART C: Reaction Stoichiometry Mass of Empty 50 mL. Beaker Mass of Beaker and Unknown Solid moles 0.00500 Liter 8.125 g 8.387 g Mass of Unknown Solid Mass of Beaker and NaCI (final heating) 8.405 g Mass of NaCI Produced (Experimental Yield of NaCI) Theoretical Yield of NaCI if Unknown Solid is Na,CO, Theoretical Yield of NaCl if Unknown Solid is NaHCO Formula of the Unknown Solid Percent Yield -grams NaCl grams NaCiExplanation / Answer
1. 0.351 g (7.976 - 7.625)
2. 0.003 moles (since Nacl and Na2CO3 combines in 2:1 mole ratio and thus 1 mole of Na2CO3 is equivalent to 2*58.441 gram of NaCl)
3. 3/5 M (Apply the formula of Molarity)
4. 0.262 g (8.387 - 8.125)
5. 0.28 g (8.405 - 8.125)
6. 0.288 g ( (2*58.441)*0.262/105.986) [Na2CO3 and NaCl combines in 1:2 mole ratio]
7. 0.182g ((1*58.441)*0.262/84.005) [NaHCO3 and NaCl combines in 1:1 mole ratio]
8. Based on given information it is not possible to calculate the formula of unknown substance. But if substance is one of Na2CO3 and NaHCO3 and based on above calculation Na2CO3 might be the solution as percentage yield can't be greater than 1 which is in case of NaHCO3 .
9. 97.2% (Percentage yield of NaCl) [(Experimental/ Theoritical)*100]
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