A volume of 505 mL of air on a cold winter day at -15 C is breathed into the lun
ID: 1033909 • Letter: A
Question
A volume of 505 mL of air on a cold winter day at -15 C is breathed into the lungs and the body temperature is 37 C. Does the volume of air become larger, smaller, or stay the same? (Assume that the pressure and amount of gas do not change.)
A sample of methane (CH4) has a volume of 25 mL at a pressure of 0.80 atm. What is the volume of the gas, in mL, at 2500 mmHg, assuming that there is no change in temperature or amount of gas?
The air in a 5.00 L tank has a pressure of 1.20 atm. If the air is transferred to a tank with a volume of 2.00 L, calculate the new pressure of the air in atm. Assume that there is no change in temperature or in amount of gas.
A sample of N2 with an initial pressure of 780. mmHg at -75 C is heated to 28 C. Calculate the final pressure. (Assume that volume and amount of gas are constant.)
Explanation / Answer
1)
Given:
Vi = 505 mL
Ti = -15.0 oC
= (-15.0+273) K
= 258 K
Tf = 37.0 oC
= (37.0+273) K
= 310 K
use:
Vi/Ti = Vf/Tf
505 mL / 258.0 K = Vf / 310.0 K
Vf = 607 mL
So, volume is increasing from 505 mL to 607 mL
2)
Given:
Vi = 25 mL
Pi = 0.8 atm
Pf = 2500.0 mm Hg
= (2500.0/760) atm
= 3.2895 atm
use:
Pi*Vi = Pf*Vf
0.8 atm * 25 mL = 3.289473684210526 atm * Vf
Vf = 6.08 mL
Answer: 6.08 mL
Only 1 question at a time please
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.