The formation of ammonia occurs via the following reaction:N2(g) + 3H2(g) ?2NH3(

Question

The formation of ammonia occurs via the following reaction:N2(g) + 3H2(g) ?2NH3(g) At equilibrium [NH3] = 0.0225 M, [N2] = 0.114 M, and [H2] = 0.342 M. a. Calculate the equilibrium constant, Keq, for the reaction. b. If 0.010 moles of H2are added to the equilibrium mixture, which direction will the reaction move to reestablish equilibrium?c. The ammonia reaction as written above is endothermic. If the temperature is raised, which direction will the reaction shift? d. What is the more appropriate symbol for Keq in the last question?

Explanation / Answer

a) N2(g) + 3H2(g) -----> 2NH3(g)

Kc = [NH3]^2/[N2][H2]^3
  
    = 0.0225^2/(0.114*0.342^3)

    = 0.111

b) after addition of 0.010 moles of H2 are added to the equilibrium mixture, the equilibrium shifts towards right side.

c) If the temperature is raised, equilibrium shift towards right side.

d) by increasing temperature, Keq increases.

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