Consider the reaction, Glucose-6-phosphate + H2O Glucose + Pi The Keq at pH 8.5
ID: 1036516 • Letter: C
Question
Consider the reaction, Glucose-6-phosphate + H2O Glucose + Pi The Keq at pH 8.5 and 25 °C is 115.
Can you determine the rate of the reaction from this information?
No, the equilibrium constant provides the equilibrium position, not the rate of reaction.
No, the concentration of glucose is needed to calculate the rate.
Yes, the rate is the reciprocal of Keq, 0.00870 in this case.
Yes, the rate is equal to the pH, 8.5 in this case.
Yes, the rate is calculated as Keq divided by the temperature, 4.60 in this case.
Explanation / Answer
Given that;
the reaction, Glucose-6-phosphate + H2O Glucose + Pi
The Keq at pH 8.5 and 25 °C is 115.
Now write the expression for Keq for this recation as follows:
Glucode-6-phosphate + H2O Glucose + Pi
Keq = (glucose_) (Pi)/(glucose-6-phosphate)
The rate of reaction from the information of equilibrium constant cannot be determined because the equilibrium constant provides the equilibrium position, not the rate of reaction.
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