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Consider the reaction, CaCO 3 ( s ) ? CaO( s ) + CO 2 ( g ) q = 178.0 kJ How muc

ID: 790118 • Letter: C

Question

Consider the reaction, CaCO3(s) ? CaO(s) + CO2(g)     q = 178.0 kJ
How much heat would be required to decompose exactly 4 mol CaCO3(s)? Answer                              A. 1780 kJ                 B. 44.5 kJ                 C. 712 kJ                 D. 89.0 kJ                 E. 178 kJ Consider the reaction, CaCO3(s) ? CaO(s) + CO2(g)     q = 178.0 kJ
How much heat would be required to decompose exactly 4 mol CaCO3(s)? 1780 kJ 44.5 kJ 712 kJ 89.0 kJ 178 kJ                 A. 1780 kJ                 B. 44.5 kJ                 C. 712 kJ                 D. 89.0 kJ                 E. 178 kJ

Explanation / Answer

heat required to decompose 4 mol CaCO3

=178.0 kJ *4 =712 KJ

option C is correct

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