Consider the reaction mechanism A + B C - with the forward rate constant k_1 and

Question

Consider the reaction mechanism A + B C - with the forward rate constant k_1 and the reverse rate constant k_1 - and C rightarrow P with the rate constant k_2. Write the expression for d[P]/dt under the following assumptions: steady state approximation pre-equilibrium Show that the mechanism paraH_2(g) 2H(g) (Step 1) and H(g) + paraH_2 rightarrow orthoH_2(g) + H(g) (Step 2) is consistent with the rate law if Step 1 is a fast equilibrium (i.e., under pre-equilibrium conditions). What is k_obs in terms of the rate constants for each step? Use the same nomenclature we have been using in class to express rate constants for each step.

Explanation / Answer

There are multiple questions here . i am allowed to answer only 1 at a time. I will answer 6th question for you.Please ask other as different question.

6.

             K1
para H2 <-----> 2H
             K2
                      K3
H + para H2 ---> H

rate = k3 [H][para H2]

write H in terms of eqn 1
k1/k2 = [H]^2/[para H2]
[H] = sqrt(k1/k2)* sqrt[Para H2]

SO, rate = rate = k3 [H][para H2]
becomes
rate = k3 sqrt(k1/k2)* sqrt[Para H2] [para H2]
         = k3* sqrt(k1/k2)* [Para H2]^3/2
          = kobs* [Para H2]^3/2
kobs= k3* sqrt(k1/k2)
here k3 = rate constant of 2nd reaction
k1= forward rate constant of 1st reaction
k2= backward rate constant of 1st reaction

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