In the following table are given the calculated mean free paths, collision diame

Question

In the following table are given the calculated mean free paths, collision diameters, and ratios of mean free path to collision diameter for four gaseous molecules all at the same temperature and pressure. Determine from this table what general relationship predicts the ratio of mean free path to collision diameter Mean free path (m/collision) Collision diameter Ratio of mean free path to collision Molecule 1.1 x 10- 4.2 x 108 7.2 x 108 2.7 x 10-10 4.5 x 10-10 3.7 x 10-10 3.6 x 10-10 diameter 4.2 x 102 9.3 x 101 1.9 x 10 2.5 x 102 2 CO 2 2 9.1 x 108 2

Explanation / Answer

Smaller one is H2 molecule, but its mean free path to collision diameter ratio is high or 420.

larger molecule is CO2, but its ratio is very low or 93.

The molecule with smaller mean free path is CO2, but it has very low ratio

the faster the molecule, it should undergo more collision per seconds and larger its mean free path

So first three statements are wrong , last one is true one.

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