In the following table each column represents a neutral atom. Fill in the gaps i
ID: 515409 • Letter: I
Question
In the following table each column represents a neutral atom. Fill in the gaps in the following table by working this problem out on a separate sheet of paper. You will need the periodic table in the "resources" drop down menu in the upper right hand corner of this question to look up atomic numbers and masses.
Part A Once you have filled in all the gaps on a separate sheet of paper, enter the four missing element symbols in the first row of the table into the answer box below. You can open the first hint to view a video that steps you through filling in the first column of the table. Enter the four missing symbols for the first row of the table from left to right, separated by commas, into the answer box below. Use the stacked super/subscripts button (available in the templates button menu above the answer entry box) to enter the symbols in the following form: mass numberatomic numberSymbol, or for example, 3517Cl.
Symbol 79Br Protons 25 82 Neutrons 30 64 Electrons 48 86 Mass no. 222 207Explanation / Answer
1)
for 2nd column
symbol = 79Br
protons = atomic number of Br = 35
mass number : 79
Neutrons = mass number - protons = 79 - 35 = 44
electrons = number of protons = 35
2)
for 3rd columsn:
protons = 25
neutrons = 30
electrons = number of protons = 25
mass no = neutrons + protons = 30 + 25 = 55
atomic number 25 is Mn
symbol : 55Mn
3)
for 4th column:
protons = number of electrons = 48
neutrons = 64
electrons = 48
mass no = neutrons + protons = 64 + 48 = 112
atomic number 48 is Cd
symbol : 112Cd
4)
for 5th column
protons = number of electrons = 86
neutrons = mass number - proton = 222 - 86 = 136
electrons = protons = 86
mass no = 222
atomic number 86 is Rn
symbol : 222Rn
5)
for 6th column:
protons = 82
neutrons = mass number - number of proton = 207 - 82 = 125
electrons = number of proton = 82
mass no = 207
atomic number 82 is Pb
symbol : 207Pb
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