Use the References to access important values if needed for this question. The f

Question

Use the References to access important values if needed for this question. The following information is given for tin at 1 atm: boiling point = 2.270E3 °C Hvap(2.270E3°C) = 1.939E3 J/g melting point = 232.0 °C Hfus(232.0°C) = 59.60 J/g specific heat solid= 0.2260 J/g ? °C specific heat liquid = 0.2430 J/g ? °C A 40.10 g sample of liquid tin at 436.0 °C is poured into a mold and allowed to cool to 23.0 °C. How many kJ of energy are released in this process. Report the answer as a positive number.

Explanation / Answer

energy released = mCpdT

with

m = 40.10 g

Cp = 0.2430 J/g.oC

dT = 23 - 436 oC

we get,

heat released = mCpdT

                       = 40.10 x 0.2430 x (23 - 436)/1000

                       = -4.024 kJ

energy released = 4.024 kJ

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.