A 0.4054 g of a sample contains bromine. The sample was reacted with silver nitr
ID: 1040216 • Letter: A
Question
A 0.4054 g of a sample contains bromine. The sample was reacted with silver nitrate and the resulting silver bromide solid was collected and d ried in the o ven. The mass of silver bromide was determined to be 37.8 mg. What is the % by mass of bromine in the original sample? A 0.4054 g of a sample contains bromine. The sample was reacted with silver nitrate and the resulting silver bromide solid was collected and d ried in the o ven. The mass of silver bromide was determined to be 37.8 mg. What is the % by mass of bromine in the original sample? silver nitrate and the resulting silver bromide solid was collected and d ried in the o ven. The mass of silver bromide was determined to be 37.8 mg. What is the % by mass of bromine in the original sample?Explanation / Answer
XBr + AgNO3------------> AgBr + XNO3
Br in AgBr wholly comes from XBr So, the Br in AgBr is equal to the mass of Br in XBr
(mol wt) 187.8 g of AgBr --------- 79.90 g of Br (mol wt)
(37.8mg) 0.0378 g of AgBr ------ ? (0.0378x79.90)/187.8 = 0.016 gms of Bromine
0.4054 g of XBr ----- 100%
0.016 g of Br--------? % = (0.016 x100)/0.4054= 3.95%
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