A 0.400kg glider is moving to the right on a frictionless,horizontal air track
ID: 1726267 • Letter: A
Question
A 0.400kg glider is moving to the right on a frictionless,horizontal air track with a speed of 0.750m/s when it makes ahead-on collision with a stationary 0.150kg glider. Find the magnitude of the final velocity of first glider ifthe collision is elastic? Find the magnitude of the final velocity of second glider ifthe collision is elastic. Find the final kinetic energy of first glider. Find the final kinetic energy of second glider. A 0.400kg glider is moving to the right on a frictionless,horizontal air track with a speed of 0.750m/s when it makes ahead-on collision with a stationary 0.150kg glider. Find the magnitude of the final velocity of first glider ifthe collision is elastic? Find the magnitude of the final velocity of second glider ifthe collision is elastic. Find the final kinetic energy of first glider. Find the final kinetic energy of second glider.Explanation / Answer
Let the masses of the two bodies are m1 and m2
the initial velocitiesare U1,U2 respectively
the finalvelocities are V1,V2 respectively.
from the law of conservation of momentum
m1*U1+m2*U2 = m1*V1+m2*V2
m1(U1-V1) = m2*(V2 - U2) ----------(1)
from the law of conservation of Kineticenergy
(1/2)m1*U12+(1/2)m2*U22 =(1/2)m1*V12+ (1/2)m2*V22
m1(U12-V12) =m2*(V22 - U22) ----------(2)
devide the equation (1) by (2) weget
U1+V1 = V2 +U2
V1 =V2 + U2 -U1
V2 = U1+V1 -U2
substitude the valueof V2 value in equation (1) weget
V1 = (m1-m2)*U1/(m1+m2) + (2m2)U2 /(m1+m2)-----------(3)
substitude the valueof V1 value in equation (1) weget
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.