7 1 6#q2 Frostburg State Unive i chemistry@ frosiburgFrostburg Canvas g.edu/mood

Question

7 1 6#q2 Frostburg State Unive i chemistry@ frosiburgFrostburg Canvas g.edu/moodle/mod/quiz/attempt.php? attempt-1 273 2 1 &scrollpos; Launch Pad Abno gin B Question 4 Tries remaining Biphenyl product theoretical yield(g) Marked out of 3 00 4-acetylbiphenyl uct Flag question 4-methylbiphenyl 4-methoxybiphenyl Check Question 5 Go look at this MSDS for phenylboronic acd ntps./www.chemoink commso Scrolil down to Section 8 which of the fellowing PPE are mentioned? se Protection. Do not use the enty for large 1 00 out o

Explanation / Answer

4- BROMO ACETOPHENONE = 3 mmol  Molar mass: 199.05 g·mol?1 weight in milli gram =?

number of moles= weight in milli gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

=  3 mmol *  199.05 g·mol?1

= 597.15 mg

4-BROMO ANISOlE = 3 mmol   187.036 g/mol weight in milli gram  =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 3 mmol * 187.036 g/mol

= 561.108 mg

4-BROMO TOLUENE = 3 mmol 171.03 g/mol  weight in milli gram  =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 3 mmol * 171.03 g/mol

= 513.09 mg

PHENYL BORONIC ACID  = 3 mmol 121.93 g/mol  weight in milli gram  =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 3 mmol * 121.93 g/mol

= 365.79 mg

SODIUM CARBONATE= 9 mmol  105.9888 g/mol weight in milli gram  =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 9 mmol *105.9888 g/mol

= 953.8992 mg

TBAB (Tetra-n-butylammonium bromide) = 2.15 mmol 322.368 g/mol weight in milli gram =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 2.15 mmol * 322.368 g/mol  

= 693.0912 mg

PALLEDIUM ACETATE = 0.004  mmol 224.5 g/mol  weight in milli gram =?

number of moles= weight in milli  gram / molar mass

weight in milli  gram =  number of milli moles* molar mass

= 0.004  mmol* 224.5 g/mol  

= 0.898 mmol

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