7 0/2 points | Previous Answers SerPSE10 7.5.OP.016. My Notes A stone with a mas

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7 0/2 points | Previous Answers SerPSE10 7.5.OP.016. My Notes A stone with a mass of 2.80 kg is moving with velocity (5.8oi 1.60j) m/s. (HINT: v v.) (a) What is the stone's kinetic energy (in J) at this velocity? Find the square of the initial velocity using the hint given, and then use the definition of kinetic energy, KE =-mv to calculate the kinetic energy. J (b) Find the net work (in J) on the stone if its velocity changes to (8.00i 4.00j) m/s. Need Help?Read It Submit Answer Save Progress Practice Another Version

Explanation / Answer

|V|=sqrt[5.82+(-1.6)2] =6.0166 m/s

Stone;s Kinetic energy

K=(1/2)mV2 =(1/2)*2.8*6.01662

K=50.68 J

b)

|V| =sqrt[82+42]=8.944 m/s

K=(1/2)*2.8*8.9442 =112 J

Work done is

W=K2-K1=112-50.68

W=61.32 J

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