Two 25.0 mL samples, one 0.200 MKOH and the other 0.200 M CH3NH2, were titrated
ID: 1048864 • Letter: T
Question
Two 25.0 mL samples, one 0.200 MKOH and the other 0.200 M CH3NH2, were titrated with 0.100 MHI. Answer each of the following questions regarding these two titrations.
A.) What is the volume of added acid at the equivalence point for KOH?
B.) What is the volume of added acid at the equivalence point for CH3NH2?
C.) Predict whether the pH at the equivalence point for each titration will be acidic, basic, or neutral.
neutral for both
D.)
Predict which titration curve will have the lowest initial pH.
neutral for KOH and basic for CH3NH2 neutral for KOH and acidic for CH3NH2 basic for KOH and neutral for CH3NH2 acidic for KOH and neutral for CH3NH2neutral for both
D.)
Predict which titration curve will have the lowest initial pH.
The initial pH will be lower for KOH. The initial pH will be lower for CH3NH2.Explanation / Answer
A)
M(KOH)*V(KOH) = M(HI)*V(HI)
0.200 *25 = 0.100 * V
V = 50 mL
Answer: 50 mL
B)
M(CH3NH2)*V(CH3NH2) = M(HI)*V(HI)
0.200 *25 = 0.100 * V
V = 50 mL
Answer: 50 Ml
C)
since KOH is strong base, solution after titration will be neutral
since CH3NH2 is weak base and hence solution will be acidic after titration
Answer: neutral for KOH and acidic for CH3NH2
D)
Lower initial pH for less basic compound
Answer:
The initial pH will be lower for CH3NH2.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.