Which is the value of the conditional formation constants, K_t of the Cd^2-EDTA

Question

Which is the value of the conditional formation constants, K_t of the Cd^2-EDTA complex, at pH=9. The Cd^2-EDTA complex has a formation constant K_t = 16.5. 0.985 0.041 0.676 16.5 0.028 Section B Find the pH of a solution prepared by dissolving 1.00 of potassium hydrogen phthate and 1 .50 g of disodium phthate in 50.0 mL of water. M_(C8H3O4K)=204.221, M_(C8H3O4K2) Calculate the pH when 50.00 mL of 0.100 M HNO_3 is mixed with 40.00 mL of 0.0750 M NaOH. Calculate the pH during the titration of 50.00 mL of a 0.1500 M methylamine with 0.1000 M HCl. K_b = 4.42 Times 10^-4. When the volume added in a) V=0 mL. b) V=50 mL c) V=75 mL. d) V=80 mL. Calculate [Mn^2+] when 50.00 mL of 0.1000 M Mn^2+ is titrated with 17.00 mL of 0.2000 M EDTA. The titration is buffered to pH 11 for which alpha_r4 = 0.81. K_f = 7.76 times 10^13

Explanation / Answer

Q7.

Kf fo Cd+2- EDTA for H = 9

Kf = 16.5

the

if pH = 9 then Kf = 0.041 from the table

so choose B

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