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Chrome File Edit View History Bookmarks People Window Help Mississippi College CHE 124 x C Each Value Below Represents x f Facebook libiscms/mod/ibis/view.php?id- 2740981 WWW.Saplinglearning.com EE Apps For quick access, place your bookmarks here on the bookmarks ba port bookmarks now Sapling Lee Sapling Learning I Mississippi College CHE 124 Fall16 BAILEY l Activities and Due Dates I HW 7 My Assignment O 11/8/2016 12:00 PM 15.9/29 10/28/2016 o4:14 PM Gradebook Attempts Score Print Calculator dic Tab Question 17 of 29 00 Map Learning 95 Each value below represents a different aqueous solution at 25 °C 00 Classify each solution as acidic, basic, or neutral. 00 Acidic Neutral Basic 00 00 00 95 lpoHa 4.07 poH-10.15 HTS 46 x 10 4 DH1 -9.1 x 10-9 loH 2.0 x 10 8 loH-1 4.6 10-2 (H1 1.0x10 7 poH 700 pHT 1.10 pH 11.97 20 Previous Give Up & View Solution Check Answer Next SExit 9 H 2016 Sapling L 20 39 partn tact cy policy 35% Thu 10:02 PM L E E Other Bookmarks Logout He Resources Assignment Information Available From: 0/27/2016 11:55 AM 11/8/2016 12:00 PM Due Date Points Possible 29 Grade Category Graded Description: Homework Policies You can check your answers. n view solutions when you complete or give up on any question. You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer in your question for each incorrect attempt at that answer. O eTextbook O Help With This Topic O Web Help & Videos O Technical Support and Bug Reports

Explanation / Answer

pH 1 to 7 considred as Acidic

pH 7 considred as Neutral

pH 7 to 14 considred as besic

1) pOH = 4.07

pH = 14 - pOH = 14 - 4.07 = 9.93 THus,

pOH = 4.07 = Besic

2) pOH = 10.15

pH = 14 - pOH = 14 - 10.15 = 3.85 THus,

pOH = 10.15 = Acidic

3) [H+] = 4.6 * 10-4

pH = -log [H+] = -log(4.6 * 10-4) = 3.33 = Acidic

4)[H+] = 9.1 * 10-9

pH = -log [H+] = -log(9.1 * 10-9) = 8.04 = Besic

5)[OH-] = 2.0 * 10-8

pOH = -log[OH-] = -log(2.0 * 10-8) = 7.69

pH = 14 - pOH = 14 - 7.69 = 6.31 = Acidic

6) [OH-] = 4.6 * 10-2

pOH = -log[OH-] = -log(4.6 * 10-2) = 1.33

pH = 14 - pOH = 14 - 1.33 = 12.67 = Besic

7) [H+] = 1.0 * 10-7

pH = -log [H+] = -log(1.0 * 10-7) = 7 = Neutral

8) pOH = 7.00

pH = 14 - pOH = 14-7 = 7 = Neutral

9)pH = 1.10 = Acidic

10) pH = 11.97 = Besic

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