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Assuming 1 T C (metric ton carbon) emitted globally into the atmosphere per pers

ID: 1050659 • Letter: A

Question

Assuming 1 T C (metric ton carbon) emitted globally into the atmosphere per person per year, calculate the per capita annual CO2 emitted in T as well as in gmol (i.e., mol) and STP m3 CO2 (STP = standard temperature & pressure, 25 degree C and 1 atm.). Also calculate the total worldwide emissions of CO2 emitted in T, for a population of ~ 7 B. Some of this, say 40%, gets fixed annually due to increased absorption into ocean. The rest contributes 2 ppm (euro 2 times 10-6 mol CO2/mol air) annual CO2 increase in the atmosphere. Calculate the total mass (in T) of air in the atmosphere.

Explanation / Answer

C + O2 = CO2

12g 44g

1000 kg x

x = 3666.67 Kg per person per year = 3.667 T per person per year

per capita annual CO2( in gmol) = 3667000 g / 44 = 8.3340 * 10^4 gmol

total worldwide emission of CO2 = 3.667 T * 7*10^9(world population) = 2.5669 * 10^10 T

annual increased absorption of CO2 = 0.4* 2.5669 * 10^10 T = 1.02676 * 10^10 T

annual unabsorbed CO2 = 2.5669 * 10^10 T- 1.02676 * 10^10 T = 1.54014*10^10 T = 1.54014*10^16 /44 gmol= 3.5*10^14 gmol

annual CO2 increase in atmosphere = 2*10^-6 mol of CO2 per one mole of air

3.5*10^14 gmol of CO2 is released per 1.75*10^20 gmol of air

total mass of air in the atmosphere = 1.75*10^20 * 29(molecular weight of air ) = 5.075e+21 g = 5.075e+15 T

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