QUESTION 6 Complete combustion of 4.5892 a particular compound that contains onl

Question

QUESTION 6 Complete combustion of 4.5892 a particular compound that contains only carbon, hydrogen and oxygen produces 10.4324 g of CO2 and 4.2705 g of H2O. The empirical formula of the compound is given by

C__________________ H______________________ O_____________ (indicate "1" if there is only one atom of a given type in the empirical formula.)

The molar mass of the compound is found to be 116.16 g/mol in a different experiment. What is the molecular formula of the compound?

C______________ H________________ O_____________________

Need help and answers please!

Explanation / Answer

mol of CO2 = mass/MW = 10.4324/44 = 0.2371

mol of H2O = mass/MW = 4.2705 / 18 = 0.23725

mol of C = 0.23725

mol of O = 0.23725*2 + 0.23725 = 0.71175

mol of H = 2*0.23725 = 0.4745

ratios:

0.71175 /0.23725 = 3

0.4745 / 0.23725 = 2

0.23725 / 0.23725 = 1

CH2O3

MW of empirical = 12+2*2 + 16*3 = 64 g/mol

so..

x times = 116.16/64 = 1.815 nearest value is 2x

so..

CH2O3 --> C2H4O6

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