QUESTION 6 Consider the second onder reactions 2A P The rate constant is k take

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QUESTION 6 Consider the second onder reactions 2A P The rate constant is k take for 75% to react? 5.7x10-3 min-1 it you start with 10.0h of reactant how many minutes wil QUESTION7 Consider the reaction below CO(g)+3H2() CH4(9)+H20(g) c 138 at 1200 K 02 mol of C0 and 0.3 mol of H2 gas are initially placed in a 1.0L container Letting Xconcentration of CO reacted leads to the following equilibrium expression Click Save and Submit to sove and submit. Chick Sove All Answers to save all ansuers Save All Ar 8 9 option command

Explanation / Answer

6)

we have:

[A]o = 10.0 g

75 % of A has reacted

So, remaining A is 25 %

[A] = 25 % of 10.0 g

= 25*10.0/100

= 2.5 g

k = 5.7*10^-3 min-1

use integrated rate law for 1st order reaction

ln[A] = ln[A]o - k*t

ln(2.5) = ln(10) - 5.7*10^-3*t

0.9163 = 2.303 - 5.7*10^-3*t

5.7*10^-3*t = 1.386

t = 243 min

Answer: 243 min

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