Using the ideal gas law, determine the percent concentration of hydrogen peroxid

Question

Using the ideal gas law, determine the percent concentration of hydrogen peroxide in a given sample.
Information given: P = 1.002 atm V = 0.047 L n = ? R = 0.08206 T = 296 K
Hydrogen Peroxide has a density of 1.02 g/mL
The balanced equation of hydrogen peroxide is: 2 H202 ---> 1 H20 + 2 O2
Initial Sample of Hydrogen Peroxide: 5 mL Using the ideal gas law, determine the percent concentration of hydrogen peroxide in a given sample.
Information given: P = 1.002 atm V = 0.047 L n = ? R = 0.08206 T = 296 K
Hydrogen Peroxide has a density of 1.02 g/mL
The balanced equation of hydrogen peroxide is: 2 H202 ---> 1 H20 + 2 O2
Initial Sample of Hydrogen Peroxide: 5 mL
Information given: P = 1.002 atm V = 0.047 L n = ? R = 0.08206 T = 296 K
Hydrogen Peroxide has a density of 1.02 g/mL
The balanced equation of hydrogen peroxide is: 2 H202 ---> 1 H20 + 2 O2
Initial Sample of Hydrogen Peroxide: 5 mL

Explanation / Answer

According to the ideal gas equation is PV = nRT

Where

T = Temperature = 296 K

P = pressure = 1.002 atm

n = No . of moles = ?

R = gas constant = 0.0821 L atm / mol - K

V= Volume of the gas = 0.047 L

Plug the values we get n = (PV)/(RT)

                                    = (1.002x0.047)/(0.0821x296)

                                    = 1.93x10-3 mol

So concentration of hydrogen peroxie , M = number of moles / volume in L

                                                             = 1.93x10-3 mol / 0.047 L

                                                            = 0.041 mol/L

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