Determine the name and formula for a compound with the following characteristics

Question

Determine the name and formula for a compound with the following characteristics.
1. Monatomic and polyatomic ions are present.
2. The ratio between positive and negative ions is one to one.
3. A group IIA element that loses one half of its total electrons upon ion formation is present
4. The polyatomic ion contains equal numbers of atoms of two nonmetallic elements.
5. The sum of the atomic numbers for the two elements involved in the polyatomic ion is 13. Determine the name and formula for a compound with the following characteristics.
1. Monatomic and polyatomic ions are present.
2. The ratio between positive and negative ions is one to one.
3. A group IIA element that loses one half of its total electrons upon ion formation is present
4. The polyatomic ion contains equal numbers of atoms of two nonmetallic elements.
5. The sum of the atomic numbers for the two elements involved in the polyatomic ion is 13.
1. Monatomic and polyatomic ions are present.
2. The ratio between positive and negative ions is one to one.
3. A group IIA element that loses one half of its total electrons upon ion formation is present
4. The polyatomic ion contains equal numbers of atoms of two nonmetallic elements.
5. The sum of the atomic numbers for the two elements involved in the polyatomic ion is 13.

Explanation / Answer

A the element looses half of its electrons on ionization and it is group II element : it is Be : beryllium. It has total 4 electrons. on ionization it looses 2 electrons. Be <==> Be^2+ + 2e-

Poly atomic ion is the negative ion as metals metal bond formation to give a polyatomin +ve ion is highly unusual.

Sum of the atomic number is 13. It is CN-.

The compound is Be(CN)2

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