Naturally found uranium consists of 99.274%, 0.720% and 0.006% (by mass). As we

Question

Naturally found uranium consists of 99.274%, 0.720% and 0.006% (by mass). As we have seen, is the isotope that can undergo a nuclear chain reaction. Most of the used in the first atomic bomb was obtained by gaseous diffusion of uranium hexafluoride, UF_6 (g). Now suppose that the UF_6 is diffused through a porous barmier and that the change in the of and in the diffused gas can be described by the equation What is the mass of in sample of the diffused analogous to that in part A? After one more cycle of gaseous diffusion, what is the percentage of in the sample? (in your calculations unrounded values from previous parts should be used.)

Explanation / Answer

C. Mass of 235U in the sample in the form of 235UF6 is 349 g/mol

Mass of 235U = 235.043 g/mol

D.

Mass of 238UF6 = 352 g/mol

Mass of 235UF6 = 349 g/mol

Separation factor: SQRT(238UF6/235UF6) =SQRT*(352/349) = 1.00429

Percentage of 235UF6 after one cycle = 1.00429 x 0.720 = 0.723%

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