e) Consider a corn yield of 7,200 kg/hectare (equivalent to 120 bushels per acre

Question

e) Consider a corn yield of 7,200 kg/hectare (equivalent to 120 bushels per acre). If 25 kg (one bushel) of corn consumed about 20m3 of water during the growing season, what is the ratio of the weight of corn to the weight of water consumed? Where does most of the water end up? Calculate the minimum quantity of irrigation water required to grow the corn (1 hectare 104m2) if the corn is grown in Phoenix AZ (annual precipitation 7.66 in) or in Lincoln, NE (28.4in). Clearly state any assumptions you make. (6)

Explanation / Answer

e)

Ratio of weight of the corn to the water consumed ?

25 kg of corn requires = 20 m3

So 7200 kg will require = 20 / 25 * 7200 = 5760 m3

So the ratio of weight of the corn to weight of the water = 7200 / 5760 = 1.25

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