This Oxidation Phosphorylation problem really confuses me since there is a lot i

ID: 1059417 • Letter: T

Question

This Oxidation Phosphorylation problem really confuses me since there is a lot involved and I can't seem to understand the calculations involved.

An explanation would help a lot and the steps to the result.

How much free energy is stored in the proton gradient established by complex 1,3 and 4 as a result of NADH oxidation?

Assume the change in pH between N and P is 0.75 units, assume membrane potential is 0.15 volts and assume the degrees is 25 degrees Celsius.

Z is charge or magnitude while F is Faraday's constant I'm not sure what the other variable is.

Computing AG for Proton Imbalance Sunne membrane trans Out AG ZF Ads RT In in

As per the given information

Delta G = RTln(H+out/H+in) +ZF Delta

Z = 2

F = 96485 C

Delta = 0.15 volts

R = 8.314

T = 298 K

ln(H+out/H+in) = 2.303 log(H+out/H+in) = 2.303[ logH+out - logH+in] = -2.303[ pHout -pHin]

Given change in pH = 0.75 = [ pHout -pHin]

Delta G = -8.314 X 298 X 2.303 (0.75) + 2 (96485) X 0.15

DeltaG = -4279.38 + 28945.5 = 24666.12 J / mole

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