6 CO 2 (g) + 6H 2 O(l) ------> 6O 2 (g)+ C 6 H 12 O 6 (s) dH=? Using the heat of

Question

6 CO2(g) + 6H2O(l) ------> 6O2(g)+ C6H12O6(s) dH=?

Using the heat of formation values from Appendix L of the 9th edition of Kotz, Treichel & Townsend (and for C6H12O6(s), the heat of formation is -1274.4 kJ/mole)

a) calculate the enthalpy change associate with the photosynthesis reaction shown above, as written

b) state whether this reaction is endothermic or exothermic

c) calculate the enthalpy change associate with the photosynthesis reaction shown above, if only 11.og CO2 were reacted with excess water

Explanation / Answer

6CO2(g) + 6H2O(l) --> C6H12O6(s) + 6O2(g)

dH reaction = dHf products - dHf reactants

Delta Hº = [6 * Delta Hf º(CO2 (g)) + 6 * Delta Hf º(H2O(l))] - - [1* Delta Hf º(C6H12O6 (s)) + 6* Delta Hf º(O2 (g))]

= [6* (-393.5) + 6* (-285.8)] - [1* (-1268) + 6* 0] =

= -2808 kJ DHc º = -2808 kJ/1 mol C6H12O6 = -2808 kJ/mol-----ANSWER

Photosynthesis is an example of an endothermic chemical reaction

Related Questions

Navigate

• Browse (All)
• Browse 6
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.