Based on the results of the above measurements, arrange the metals according to

Question

Based on the results of the above measurements, arrange the metals according to their increasing activity. Why did you reach this conclusion? Using the data for cell combinations 1 and 3, predict the cell potential for cell combination 4. volts How does this value compare with your experimental value listed in the table? Use the E degree value for Cu/Cu^+2 half reaction given in Table 24.1 and the cell emf value for cell combination 3 to calculate the E degree Value for the Zn/Zn^+2 half-cell reaction._volts Use the E degree value for Cu/Cu^+2 half reaction given in Table 24.1 and the cell emf value for cell combination 1 to calculate the E degree Value for the Sn/Sn^+2 half-cell reaction._volts Use the values for 5 and 6 to predict the potential for call combination 4 volts How does this value compare with your experimental value from 4 ?

Explanation / Answer

Q1

The higher reduction potentials... the more stable metals we have

so..

Sn2+ + 2 e Sn(s) 0.13

Pb2+ + 2 e Pb(s) 0.126

Zn2+ + 2 e Zn(s) 0.7618

Cu2+ + 2 e Cu(s) +0.337

Then, Cu > Pb > Sn > Pb

Q2

the conclusion arises from the stability or tendency of the metal ion to form a solid metal...

Q3

For combination 4...

Sn/Sn+2 and Zn/Zn2

Zn2+ + 2 e Zn(s) 0.7618

Sn2+ + 2 e Sn(s) 0.13

E°cell = -0.13 --0.7618 = 0.6318 VV

Q5

For

Zn2+ + 2 e Zn(s) 0.7618

Cu2+ + 2 e Cu(s) +0.337

Ecell = Ered - Eox = 0.337 - -0.7618 = 1.0988 V

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