I need help with question 11-26 please had a volume of 1000 mL. Find the pH at t

Question

I need help with question 11-26 please

had a volume of 1000 mL. Find the pH at the following volumes of acid added and make a graph of pH versus v 0, 1, 5, 9, 10, 11, 15, 19, 20, and 22 ml 11-24 A 10000 ml, aliquot of 0.100 M diprotic acid H.A (phi 4.00, pA: 8.00) was titrated with 1.00 M NaoH, Find the pH at the following volumes of base added and make a graph of pH ver- sus vb: vb m 0, 1, 5. 9, 10, 11 15, 19, 20, and 22 ml. 11-25. Calculate the pH at 10.0 mL intervals (from 0 to 100 ml in the titration of 40.0 ml. of 0.100 M piperazine with 0.100 M Hci l-Yo. Calculate the pH when 25.0 ml of o020 0 M 2-aminophenol has been titrated with 10.9 mL of 0015 0 M HCIOA. 11-27. Consider the titration of 50.0 mL of 0.100 M sodium glyci- nate, H2NCH2CO.Na, with 0.100 M HCI. (a) Calculate the pH at the second equivalence point. (b) Show that our approximate method of calculations gives incor- rect (physically unreasonable) values of pH at V, 90.0 and V. 101.0 ml 11-28. A solution containing 0.100 M glutamic acid (the molecule with no net charge) was titrated to its first equivalence point with 0.0250 M RboH. (a) Draw the structures of reactants and products. (b) Calculate the pH at the first equivalence point. 11-29, Find the pH of the solution when 0.010 0 M tyrosine is titrated to the equivalence point with 0.004 00 M HCIO 11-30. This problem deals with the amino acid cysteine, which we will abbreviate HzC. 224

Explanation / Answer

mol of 2- amino phenol = 0.025lit * 0.020 mol / 1 lit = 5*10-4 mol of 2-amino phenol
mol of HClO4 = 0.0109 lit * 0.015 mol / 1 lit = 1.635*10-4 mol of HClO4
HClO4 is a strong acid and an limiting agent and 2 aminoPhenol is excess,
mol of excess 2 amino phenol (leftover) = (5 - 1.635)*10-4 = 3.365 * 10-4 mol
volume = 10.9 + 25 = 35.9 mL = 0.0359 lit
concentration of OH- = 3.365 * 10-4 mol /  0.0359 lit = 9.37325 * 10-3 M
POH = -log10[ 9.37325 * 10-3] = 2.028109
PH + POH = 14
PH = 14 - 2.0281 = 11.97

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.