<p><span style=\"font-size: medium; font-family: times new roman,times;\">If the

Question

<p><span>If the average molecular weight of a deoxynucleotide monophosphate (dNMP) or base is 330, hence base pair is 660, <strong>how much genomic DNA would an <em>E. coli</em> cell contain</strong><strong>?</strong> The <em>E. coli</em> genome contains 4.6 * 10⁶ base pairs in a single chromosome. <strong>How much DNA would 1 million (10⁶) <em>E. coli </em>cells contain?</strong></span><em><br /></em></p>

Explanation / Answer

It is simple. since the E. coli cell contain 4.6 * 106 bp, so it will have 2.3 * 106 dNMP.[ 4.6 * 106/2]

so, 1 million of the E coli cell will contain (2.3 * 106) * 106 ie 2.3 * 1012 DNA

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