When mass M is at the position shown, it is sliding down the inclined part of a

Question

When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 1.93 m/s. The mass stops a distance S2 = 1.9 m along the level part of the slide. The distance S1 = 1.18 m and the angle ? = 36.90

When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 1.93 m/s. The mass stops a distance S2 = 1.9 m along the level part of the slide. The distance S1 = 1.18 m and the angle ? = 36.90 degree. Calculate the coefficient of kinetic friction for the mass on the surface.

Explanation / Answer

Conservation of Energy
KE + PE = energy dissipated by friction on the slope + energy dissipated by friction on the flat
(1/2) M v^2 + M g S1 sin ? = S1 u M g cos ? + S2 u M g
Solve for u:
=> u = [(1/2) v^2 + g S1 sin ?]/[S1 g cos ? + S2 g]= 0.315

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